moectf2020 write up for 赤道企鹅，永远滴神

感觉这一题其实比上一题简单，但是分倒是比上一题多XD

直接逐个字符匹配一遍就行，时间复杂度O(N)

以及文件读写还是Java写的方便（咱不会python…qwq

import java.util.*;
import java.lang.*;
import java.io.*;

public class Test
{

    public static int searchString(String path)
    {
        File file = new File(path);
        int num = 0;

        if(file.isDirectory())//if the variable "file" is a directory, files in it will be searched in recursion
        {
            boolean exist = false;
            File[] files = file.listFiles();

            for(File f:files)
            {
                num += searchString(path+"\\"+f.getName());
            }
            return num;
        }
        else
        {
            try (FileInputStream fileInputStream = new FileInputStream(file))
            {
                int c, index = 0;
                boolean pd = false;
                char[] eqqie = {'E','q','q','i','e','N','B','!'};
                while(true)//EOF
                {
                    c = fileInputStream.read();
                    if(index<8)
                    {
                        if(c == eqqie[index])
                        {
                            index++;
                            continue;
                        }
                        else
                            return 0;
                    }
                    if((c>='A'&&c<='Z')||(c>='a'&&c<='z')||(c>='0'&&c<='9'))
                    {
                        pd = true;
                    }
                    else
                    {
                        if(pd)
                            num++;
                        pd = false;
                        if(c == -1)
                            return num;
                    }
                }
            }
            catch (Exception e)
            {
                System.out.print("\n"+file.getAbsolutePath());
                e.printStackTrace();
            }
            return num;
        }
    }

    public static void main(String[] args)
    {
        System.out.println(searchString(args[0]));
    }
}

base64编码即得flag

moectf{MTgyNDI2}